Friday, April 3, 2009

April 4, 2009 - Homework, Probability

Complete the following exercises from your textbook
Elementary Statistics—Picturing the World:

1. Section 3.1, Exercise #14, p. 125

2. Section 3.1, Exercise #20, p. 126

3. Section 3.2, Exercise #16, p. 136

4. Section 3.3, Exercise #18, p. 146
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10 comments:

  1. AnonymousApril 4, 2009 at 10:17 AM

    Tonya, Scott, Rick

    1. 84%
    2. 22%
    3. 50.4%
    4. A. 33%
    B. 83%
    C. 66%

    ReplyDelete
  2. AnonymousApril 4, 2009 at 10:38 AM

    Tonya,Scott,Rick

    correction on 4.C. it is actually 67%

    ReplyDelete
  3. AnonymousApril 4, 2009 at 10:42 AM

    Tonya,Scott,Rick

    Correction on 3. it is actually 30%

    ReplyDelete
  4. AlexApril 4, 2009 at 10:46 AM

    Jace, Justin, Alex

    #14: we take 5296 since the number has to be over 1000, which means we subtract 1000 from 6296, and divide it by 6296 to get .8411, or 84%.

    #20: between 35 and 44 years old we have a frequency of 28.4. The total frequency of all voters is 129.5. We take 129.5 and divide it by 28.4 is 4.5598591549295774647887323943662 or 5% if we round it up.

    #16: with a 60% chance of survival, and 50% heal damage done, we must also consider the chances of not surviving, and no healing done.

    P(60 and 50) = P(60) * P(50|60). Since these two are independent of each other:
    P(60 and 50) =P(60) *P(50)
    60/100* 50/100 =.3 or 30% chance to survive and heal

    #18:
    A: since we’re dealing with one or the other:
    P(5 or 6) = P(5) + P(6)
    We can turn this into a fraction of 1/6 + 1/6 which equals .33 or 33%

    B:
    Less than 5 = 1, 2, 3, 4 OR 1, 3
    4/6 or 2/6 – 1/6 = 5/6 or .83 or 83%

    C:
    Rolling 3 = 1/6 or 2, 4, 6, or 3/6
    4/6 or .66 or 66%

    ReplyDelete
  5. rickApril 4, 2009 at 10:59 AM

    Robinson, Drake, Bailey, Dossey
    1. Section 3.1, Exercise #14, p. 125
    A company that selects employees for random drug tests. The company uses a
    computer to select randomly employee numbers that range from 1 to 6296

    Find the probability of selecting a number greater than 1000
    There is a 84.1 percent probability of selecting a number greater than 1000

    2. Section 3.1, Exercise #20, p. 126
    Age of Voter------frequency
    18-20----------------4.8
    21-24----------------7.3
    25-34----------------20.4
    35-44----------------28.4
    45-64----------------43.7
    65+------------------24.9

    The probability of a voter chosen from random between 35-44 is 22%

    3. Section 3.2, Exercise #16, p. 136
    There is a 30% chance that the patient survives surgery and the heart damage heals.

    4. Section 3.3, Exercise #18, p. 146
    You roll a die. Find each pobability.
    a. .333
    b. .833
    c. .666

    ReplyDelete
  6. BryanApril 4, 2009 at 11:11 AM

    1) The probability of selecting a number greater than 1000 is 0.841.
    2) The probability that a voter chosen at random at random is between 35 and 44 years old is 0.219.
    3)60/100 x 50/100 or
    6/10 x 5/10 = 30/100
    = 0.3 or 30% chance of surviving surgery and heart damage heals.
    4) (a)Rolling a 6 or a number greater than 4.
    1/6+2/6-1/6=2/6=1/3 or 0.33 or 33%
    (b)Rolling a number less than 5 or an odd number. 4/6+3/6-2/6=5/6 or 0.83 or 83%
    (c)Rolling a 3 or an even number.
    1/6+3/6-2/6=2/6 or 1/3 or 0.33 or 33%
    Group made up of Sheila W., Nick N., and Bryan S.

    ReplyDelete
  7. karolynApril 4, 2009 at 11:50 AM

    14.)84.1%
    20.)28.4%
    16.).30% survive and heal
    18.)a-33%
    b-83%
    c-33%

    ReplyDelete
  8. UnknownApril 29, 2009 at 7:23 PM

    1. 84.1%
    2. 99.9%
    3. 30%
    4.
    A) 1/3 or 33.3%
    B) 5/6 or 83.3%
    C) 2/3 or 66.7%

    ReplyDelete
  9. AnonymousOctober 6, 2015 at 2:17 AM

    This comment has been removed by the author.

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  10. AnonymousOctober 6, 2015 at 5:13 AM

    Along those of the Probabilities which is of course been one of the chapter in statistics also there are enough piece of the ideas which will force you to be updated with their guidelines. statistics homework help

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